2(m+3)+4m=18

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Solution for 2(m+3)+4m=18 equation: 



2(m+3)+4m=18

We move all terms to the left:

2(m+3)+4m-(18)=0

We add all the numbers together, and all the variables

4m+2(m+3)-18=0

We multiply parentheses

4m+2m+6-18=0

We add all the numbers together, and all the variables

6m-12=0

We move all terms containing m to the left, all other terms to the right

6m=12

m=12/6

m=2

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