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9x+3(2x+4)=5(x+3)
We move all terms to the left:
9x+3(2x+4)-(5(x+3))=0
We multiply parentheses
9x+6x-(5(x+3))+12=0
We calculate terms in parentheses: -(5(x+3)), so:We add all the numbers together, and all the variables
5(x+3)
We multiply parentheses
5x+15
Back to the equation:
-(5x+15)
15x-(5x+15)+12=0
We get rid of parentheses
15x-5x-15+12=0
We add all the numbers together, and all the variables
10x-3=0
We move all terms containing x to the left, all other terms to the right
10x=3
x=3/10
x=3/10
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