4x+(3x-2)=6

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Solution for 4x+(3x-2)=6 equation: 



4x+(3x-2)=6

We move all terms to the left:

4x+(3x-2)-(6)=0

We get rid of parentheses

4x+3x-2-6=0

We add all the numbers together, and all the variables

7x-8=0

We move all terms containing x to the left, all other terms to the right

7x=8

x=8/7

x=1+1/7

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