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9x(x-6)=(2x+2)(x-6)
We move all terms to the left:
9x(x-6)-((2x+2)(x-6))=0
We multiply parentheses
9x^2-54x-((2x+2)(x-6))=0
We multiply parentheses ..
9x^2-((+2x^2-12x+2x-12))-54x=0
We calculate terms in parentheses: -((+2x^2-12x+2x-12)), so:We add all the numbers together, and all the variables
(+2x^2-12x+2x-12)
We get rid of parentheses
2x^2-12x+2x-12
We add all the numbers together, and all the variables
2x^2-10x-12
Back to the equation:
-(2x^2-10x-12)
9x^2-54x-(2x^2-10x-12)=0
We get rid of parentheses
9x^2-2x^2-54x+10x+12=0
We add all the numbers together, and all the variables
7x^2-44x+12=0
a = 7; b = -44; c = +12;
Δ = b2-4ac
Δ = -442-4·7·12
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-40}{2*7}=\frac{4}{14} =2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+40}{2*7}=\frac{84}{14} =6 $
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