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+4=1/3(Y+6)
We move all terms to the left:
+4-(1/3(Y+6))=0
Domain of the equation: 3(Y+6))!=0We multiply all the terms by the denominator
Y∈R
-(1+4*3(Y+6))=0
We calculate terms in parentheses: -(1+4*3(Y+6)), so:
1+4*3(Y+6)
determiningTheFunctionDomain 4*3(Y+6)+1
Wy multiply elements
12Y(Y+1
Back to the equation:
-(12Y(Y+1)
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| 320 =x+619 | | 22.50=3.75+1.25x | | 0+7y=7 | | 1/2x×-3/4=3/8-5/8x | | 2x^2+3+x^2+28=180 | | 8x-0=3 | | 6+-3k=3 | | x+(-21)=-4 | | 5x-8=13+7x+84 | | 5/3-1/3=1/x | | 9x+x-5x=70 | | 18=0.75x | | x-(-20)=4 | | 8x-5x+6x=54 | | 9x+21=20x-45 | | 2(z+1)=18 | | 4(2x-8)=3(2-3x) | | 8x+3+2x+15=180 | | 0+14y=20 | | 9w=−81 | | 3(x+5)=7x-8 | | 2b+9=7 | | (15x-7)=360 | | (h–4)(h–10)=0 | | 3x+2(4x+2)=5x-8 | | .(r+2)(r+13)=0 | | (2x-2)+x=45 | | 0-10y=-18 | | (z-5)(z-1)-z^2=-13 | | 12t-18=-52 | | 2x2-16x+20=0 | | 4y-2/4-y/6=2 |