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9x(x-1)=72
We move all terms to the left:
9x(x-1)-(72)=0
We multiply parentheses
9x^2-9x-72=0
a = 9; b = -9; c = -72;
Δ = b2-4ac
Δ = -92-4·9·(-72)
Δ = 2673
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2673}=\sqrt{81*33}=\sqrt{81}*\sqrt{33}=9\sqrt{33}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9\sqrt{33}}{2*9}=\frac{9-9\sqrt{33}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9\sqrt{33}}{2*9}=\frac{9+9\sqrt{33}}{18} $
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