8+(4/5b)=(9/10b)

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Solution for 8+(4/5b)=(9/10b) equation: 



8+(4/5b)=(9/10b)

We move all terms to the left:

8+(4/5b)-((9/10b))=0



Domain of the equation: 5b)!=0

b!=0/1

b!=0

b∈R





Domain of the equation: 10b))!=0

b!=0/1

b!=0

b∈R



We add all the numbers together, and all the variables

(+4/5b)-((+9/10b))+8=0

We get rid of parentheses

4/5b-((+9/10b))+8=0

We calculate fractions


40b/50b^2+(-((+9*5b)/50b^2+8=0

We calculate fractions

We do not support ebpression: b^4

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