If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9x(4x-11)=46
We move all terms to the left:
9x(4x-11)-(46)=0
We multiply parentheses
36x^2-99x-46=0
a = 36; b = -99; c = -46;
Δ = b2-4ac
Δ = -992-4·36·(-46)
Δ = 16425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{16425}=\sqrt{225*73}=\sqrt{225}*\sqrt{73}=15\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-99)-15\sqrt{73}}{2*36}=\frac{99-15\sqrt{73}}{72} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-99)+15\sqrt{73}}{2*36}=\frac{99+15\sqrt{73}}{72} $
| -12=(3x-9)+15 | | 5|4w-2|=2|w+10| | | 2d+8=6(-d-7) | | (2x-18)+(x+54)=180 | | 14+19q=20q | | x+25=154 | | 20g-20=20+5g+19g | | (3x+7)+(x+45)=180 | | -9c-15=-2c+20 | | F=2x+3+36·2x−22x+5−2·2x+3−4·2x+1−6·2x−1 | | 22=j+13 | | (6x-27)=(3x+15) | | (2x-1)/3=x+2 | | e-6=10 | | 2(4x-6)+2(x)=324 | | (5x-4)=(x+8) | | (2x+10)=(4x-18) | | 28-2/5y=24 | | 30=x/49315.07 | | 21x-7+x=36 | | -23+8m=-3+6(5-7m) | | 30=x/(18000000/366) | | (5p+1)^2=12 | | (x+18)+(2x+12)=180 | | -7r=5-6r | | 18x-10=10x+30 | | 20v+19-13v=-3v-11 | | 3r=2(2r-2)-r | | 14j+4-1=-12+15j | | 400+3x=12x-5000 | | v=3v-30+6v-15+27 | | -4(4x-7)+3=-16x+31 |