(6x-27)=(3x+15)

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Solution for (6x-27)=(3x+15) equation: 



(6x-27)=(3x+15)

We move all terms to the left:

(6x-27)-((3x+15))=0

We get rid of parentheses

6x-((3x+15))-27=0



We calculate terms in parentheses: -((3x+15)), so:

(3x+15)

We get rid of parentheses

3x+15

Back to the equation:

-(3x+15)



We get rid of parentheses

6x-3x-15-27=0

We add all the numbers together, and all the variables

3x-42=0

We move all terms containing x to the left, all other terms to the right

3x=42

x=42/3

x=14

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