9u-2+2(2u+5)=-3(3u+2)

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Solution for 9u-2+2(2u+5)=-3(3u+2) equation: 



9u-2+2(2u+5)=-3(3u+2)

We move all terms to the left:

9u-2+2(2u+5)-(-3(3u+2))=0

We multiply parentheses

9u+4u-(-3(3u+2))+10-2=0



We calculate terms in parentheses: -(-3(3u+2)), so:

-3(3u+2)

We multiply parentheses

-9u-6

Back to the equation:

-(-9u-6)



We add all the numbers together, and all the variables

13u-(-9u-6)+8=0

We get rid of parentheses

13u+9u+6+8=0

We add all the numbers together, and all the variables

22u+14=0

We move all terms containing u to the left, all other terms to the right

22u=-14

u=-14/22

u=-7/11

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