(x+1)(4+5)=(x-4)(3-5)

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Solution for (x+1)(4+5)=(x-4)(3-5) equation: 



(x+1)(4+5)=(x-4)(3-5)

We move all terms to the left:

(x+1)(4+5)-((x-4)(3-5))=0

We add all the numbers together, and all the variables

(x+1)9-((x-4)(-2))=0

We multiply parentheses

9x-((x-4)(-2))+9=0

We multiply parentheses ..

9x-((-2x+8))+9=0



We calculate terms in parentheses: -((-2x+8)), so:

(-2x+8)

We get rid of parentheses

-2x+8

Back to the equation:

-(-2x+8)



We get rid of parentheses

9x+2x-8+9=0

We add all the numbers together, and all the variables

11x+1=0

We move all terms containing x to the left, all other terms to the right

11x=-1

x=-1/11

x=-1/11

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