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9q^2-36q+16=(3q-4)(3q-4)
We move all terms to the left:
9q^2-36q+16-((3q-4)(3q-4))=0
We multiply parentheses ..
9q^2-((+9q^2-12q-12q+16))-36q+16=0
We calculate terms in parentheses: -((+9q^2-12q-12q+16)), so:We add all the numbers together, and all the variables
(+9q^2-12q-12q+16)
We get rid of parentheses
9q^2-12q-12q+16
We add all the numbers together, and all the variables
9q^2-24q+16
Back to the equation:
-(9q^2-24q+16)
9q^2-36q-(9q^2-24q+16)+16=0
We get rid of parentheses
9q^2-9q^2-36q+24q-16+16=0
We add all the numbers together, and all the variables
-12q=0
q=0/-12
q=0
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