b-(1+6b)=-3(7b-5)

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Solution for b-(1+6b)=-3(7b-5) equation: 



b-(1+6b)=-3(7b-5)

We move all terms to the left:

b-(1+6b)-(-3(7b-5))=0

We add all the numbers together, and all the variables

b-(6b+1)-(-3(7b-5))=0

We get rid of parentheses

b-6b-(-3(7b-5))-1=0



We calculate terms in parentheses: -(-3(7b-5)), so:

-3(7b-5)

We multiply parentheses

-21b+15

Back to the equation:

-(-21b+15)



We add all the numbers together, and all the variables

-5b-(-21b+15)-1=0

We get rid of parentheses

-5b+21b-15-1=0

We add all the numbers together, and all the variables

16b-16=0

We move all terms containing b to the left, all other terms to the right

16b=16

b=16/16

b=1

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