9n+3(2n-3)=-(-2n+19)

Solution for 9n+3(2n-3)=-(-2n+19) equation:

9n+3(2n-3)=-(-2n+19)

We move all terms to the left:

9n+3(2n-3)-(-(-2n+19))=0

We multiply parentheses

9n+6n-(-(-2n+19))-9=0


We calculate terms in parentheses: -(-(-2n+19)), so:

-(-2n+19)

We get rid of parentheses

2n-19

Back to the equation:

-(2n-19)


We add all the numbers together, and all the variables

15n-(2n-19)-9=0

We get rid of parentheses

15n-2n+19-9=0

We add all the numbers together, and all the variables

13n+10=0

We move all terms containing n to the left, all other terms to the right

13n=-10

n=-10/13

n=-10/13