5(x-3)+x=41

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Solution for 5(x-3)+x=41 equation: 



5(x-3)+x=41

We move all terms to the left:

5(x-3)+x-(41)=0

We add all the numbers together, and all the variables

x+5(x-3)-41=0

We multiply parentheses

x+5x-15-41=0

We add all the numbers together, and all the variables

6x-56=0

We move all terms containing x to the left, all other terms to the right

6x=56

x=56/6

x=9+1/3

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