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9n(9n+9)=0
We multiply parentheses
81n^2+81n=0
a = 81; b = 81; c = 0;
Δ = b2-4ac
Δ = 812-4·81·0
Δ = 6561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6561}=81$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(81)-81}{2*81}=\frac{-162}{162} =-1 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(81)+81}{2*81}=\frac{0}{162} =0 $
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