(a+4)/21-(3a)/21=(a+7)/5

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Solution for (a+4)/21-(3a)/21=(a+7)/5 equation: 



(a+4)/21-(3a)/21=(a+7)/5

We move all terms to the left:

(a+4)/21-(3a)/21-((a+7)/5)=0

We calculate fractions


(-15a^2+a+4)/()+(-((a+7)*21)/()=0



We calculate terms in parentheses: +(-((a+7)*21)/(), so:

-((a+7)*21)/(

We multiply all the terms by the denominator


-((a+7)*21)



We calculate terms in parentheses: -((a+7)*21), so:

(a+7)*21

We multiply parentheses

21a+147

Back to the equation:

-(21a+147)



We get rid of parentheses

-21a-147

Back to the equation:

+(-21a-147)



We get rid of parentheses

(-15a^2+a+4)/()-21a-147=0

We multiply all the terms by the denominator


(-15a^2+a+4)-21a*()-147*()=0

We add all the numbers together, and all the variables

(-15a^2+a+4)-21a*()=0

We get rid of parentheses

-15a^2+a-21a*()+4=0

We move all terms containing a to the left, all other terms to the right

-15a^2+a-21a*()=-4

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