9m+3m=16/4m

Solution for 9m+3m=16/4m equation:

9m+3m=16/4m

We move all terms to the left:

9m+3m-(16/4m)=0


Domain of the equation: 4m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

9m+3m-(+16/4m)=0

We add all the numbers together, and all the variables

12m-(+16/4m)=0

We get rid of parentheses

12m-16/4m=0

We multiply all the terms by the denominator


12m*4m-16=0

Wy multiply elements

48m^2-16=0

a = 48; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·48·(-16)
Δ = 3072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3072}=\sqrt{1024*3}=\sqrt{1024}*\sqrt{3}=32\sqrt{3}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{3}}{2*48}=\frac{0-32\sqrt{3}}{96}
=-\frac{32\sqrt{3}}{96}
=-\frac{\sqrt{3}}{3}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{3}}{2*48}=\frac{0+32\sqrt{3}}{96}
=\frac{32\sqrt{3}}{96}
=\frac{\sqrt{3}}{3}
$