3x+2=(2x+20)2

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Solution for 3x+2=(2x+20)2 equation: 



3x+2=(2x+20)2

We move all terms to the left:

3x+2-((2x+20)2)=0



We calculate terms in parentheses: -((2x+20)2), so:

(2x+20)2

We multiply parentheses

4x+40

Back to the equation:

-(4x+40)



We get rid of parentheses

3x-4x-40+2=0

We add all the numbers together, and all the variables

-1x-38=0

We move all terms containing x to the left, all other terms to the right

-x=38

x=38/-1

x=-38

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