9g=3(-4+5g)g=

Solution for 9g=3(-4+5g)g= equation:

9g=3(-4+5g)g=

We move all terms to the left:

9g-(3(-4+5g)g)=0

We add all the numbers together, and all the variables

9g-(3(5g-4)g)=0


We calculate terms in parentheses: -(3(5g-4)g), so:

3(5g-4)g

We multiply parentheses

15g^2-12g

Back to the equation:

-(15g^2-12g)


We get rid of parentheses

-15g^2+9g+12g=0

We add all the numbers together, and all the variables

-15g^2+21g=0

a = -15; b = 21; c = 0;
Δ = b2-4ac
Δ = 212-4·(-15)·0
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-21}{2*-15}=\frac{-42}{-30}
=1+2/5
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+21}{2*-15}=\frac{0}{-30}
=0
$