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(2x-7)(x-8)=0
We multiply parentheses ..
(+2x^2-16x-7x+56)=0
We get rid of parentheses
2x^2-16x-7x+56=0
We add all the numbers together, and all the variables
2x^2-23x+56=0
a = 2; b = -23; c = +56;
Δ = b2-4ac
Δ = -232-4·2·56
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-9}{2*2}=\frac{14}{4} =3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+9}{2*2}=\frac{32}{4} =8 $
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