9d+2d+d+3=5(3d-4)

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Solution for 9d+2d+d+3=5(3d-4) equation: 



9d+2d+d+3=5(3d-4)

We move all terms to the left:

9d+2d+d+3-(5(3d-4))=0

We add all the numbers together, and all the variables

12d-(5(3d-4))+3=0



We calculate terms in parentheses: -(5(3d-4)), so:

5(3d-4)

We multiply parentheses

15d-20

Back to the equation:

-(15d-20)



We get rid of parentheses

12d-15d+20+3=0

We add all the numbers together, and all the variables

-3d+23=0

We move all terms containing d to the left, all other terms to the right

-3d=-23

d=-23/-3

d=7+2/3

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