10+3y=7(y-2)

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Solution for 10+3y=7(y-2) equation: 



10+3y=7(y-2)

We move all terms to the left:

10+3y-(7(y-2))=0



We calculate terms in parentheses: -(7(y-2)), so:

7(y-2)

We multiply parentheses

7y-14

Back to the equation:

-(7y-14)



We get rid of parentheses

3y-7y+14+10=0

We add all the numbers together, and all the variables

-4y+24=0

We move all terms containing y to the left, all other terms to the right

-4y=-24

y=-24/-4

y=+6

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