If it's not what You are looking for type in the equation solver your own equation and let us solve it.
9c^2+21c+10=0
a = 9; b = 21; c = +10;
Δ = b2-4ac
Δ = 212-4·9·10
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-9}{2*9}=\frac{-30}{18} =-1+2/3 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+9}{2*9}=\frac{-12}{18} =-2/3 $
| -16t^2+192t=300 | | F(a)=9.3 | | 9x+5x=58 | | 2x-7=23+6x | | 7x+221=360 | | 5x-2=5x+9 | | 7^x=51 | | 75x=2x | | 27-7/8x=-7/8x+27 | | 1/3x+2=1/6×+4/3 | | 21+15×5-y+14=88 | | 7x+12=3x+72 | | 7+30x=15x+42 | | 20m+60=100 | | 1/3z=-5 | | 2x^2+10x=52/105 | | 20×-12y=-180 | | 81g2+0+63=0 | | 81g2+54+9=0 | | Y+0.4y=58 | | (D^4+8D^2+16)y=3 | | 10x+2x=2x+5 | | 10k+4=k+13 | | 6y+10=3y+4 | | 4x+13=-23-3x | | 3|x−6|−19=2 | | 310=x9 | | 5x-5=241/3 | | (-2,-4)m=-2.5 | | y+0.2=42 | | -2=v-5-3 | | 6(6y-3)+16=4(2y+1)+12 |