6(6y-3)+16=4(2y+1)+12

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Solution for 6(6y-3)+16=4(2y+1)+12 equation:



6(6y-3)+16=4(2y+1)+12
We move all terms to the left:
6(6y-3)+16-(4(2y+1)+12)=0
We multiply parentheses
36y-(4(2y+1)+12)-18+16=0
We calculate terms in parentheses: -(4(2y+1)+12), so:
4(2y+1)+12
We multiply parentheses
8y+4+12
We add all the numbers together, and all the variables
8y+16
Back to the equation:
-(8y+16)
We add all the numbers together, and all the variables
36y-(8y+16)-2=0
We get rid of parentheses
36y-8y-16-2=0
We add all the numbers together, and all the variables
28y-18=0
We move all terms containing y to the left, all other terms to the right
28y=18
y=18/28
y=9/14

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