9b=7b/3b

Solution for 9b=7b/3b equation:

9b=7b/3b

We move all terms to the left:

9b-(7b/3b)=0


Domain of the equation: 3b)!=0

b!=0/1

b!=0

b∈R


We add all the numbers together, and all the variables

9b-(+7b/3b)=0

We get rid of parentheses

9b-7b/3b=0

We multiply all the terms by the denominator


9b*3b-7b=0

We add all the numbers together, and all the variables

-7b+9b*3b=0

Wy multiply elements

27b^2-7b=0

a = 27; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·27·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*27}=\frac{0}{54}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*27}=\frac{14}{54}
=7/27
$