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1/3y-1=1/10y
We move all terms to the left:
1/3y-1-(1/10y)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
Domain of the equation: 10y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
1/3y-(+1/10y)-1=0
We get rid of parentheses
1/3y-1/10y-1=0
We calculate fractions
10y/30y^2+(-3y)/30y^2-1=0
We multiply all the terms by the denominator
10y+(-3y)-1*30y^2=0
Wy multiply elements
-30y^2+10y+(-3y)=0
We get rid of parentheses
-30y^2+10y-3y=0
We add all the numbers together, and all the variables
-30y^2+7y=0
a = -30; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-30)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-30}=\frac{-14}{-60} =7/30 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-30}=\frac{0}{-60} =0 $
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