(1/7)(3x+2)-(1/5)=2

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Solution for (1/7)(3x+2)-(1/5)=2 equation: 



(1/7)(3x+2)-(1/5)=2

We move all terms to the left:

(1/7)(3x+2)-(1/5)-(2)=0



Domain of the equation: 7)(3x+2)!=0

x∈R



determiningTheFunctionDomain
(1/7)(3x+2)-2-(1/5)=0

We add all the numbers together, and all the variables

(+1/7)(3x+2)-2-(+1/5)=0

We get rid of parentheses

(+1/7)(3x+2)-2-1/5=0

We multiply parentheses ..

(+3x^2+1/7*2)-2-1/5=0

We calculate fractions


((+3x^2+1*5)/()+()/()-2=0

We can not solve this equation

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