(5/2)k=-5

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Solution for (5/2)k=-5 equation: 



(5/2)k=-5

We move all terms to the left:

(5/2)k-(-5)=0



Domain of the equation: 2)k!=0

k!=0/1

k!=0

k∈R



We add all the numbers together, and all the variables

(+5/2)k-(-5)=0

We add all the numbers together, and all the variables

(+5/2)k+5=0

We multiply parentheses

5k^2+5=0

a = 5; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·5·5
Δ = -100
Delta is less than zero, so there is no solution for the equation

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