9a+3=3(a-1)+6

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Solution for 9a+3=3(a-1)+6 equation:



9a+3=3(a-1)+6
We move all terms to the left:
9a+3-(3(a-1)+6)=0
We calculate terms in parentheses: -(3(a-1)+6), so:
3(a-1)+6
We multiply parentheses
3a-3+6
We add all the numbers together, and all the variables
3a+3
Back to the equation:
-(3a+3)
We get rid of parentheses
9a-3a-3+3=0
We add all the numbers together, and all the variables
6a=0
a=0/6
a=0

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