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120/10=n*n
We move all terms to the left:
120/10-(n*n)=0
We add all the numbers together, and all the variables
-(+n*n)+120/10=0
We add all the numbers together, and all the variables
-(+n*n)+12=0
We get rid of parentheses
-n*n+12=0
Wy multiply elements
-1n^2+12=0
a = -1; b = 0; c = +12;
Δ = b2-4ac
Δ = 02-4·(-1)·12
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3}}{2*-1}=\frac{0-4\sqrt{3}}{-2} =-\frac{4\sqrt{3}}{-2} =-\frac{2\sqrt{3}}{-1} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3}}{2*-1}=\frac{0+4\sqrt{3}}{-2} =\frac{4\sqrt{3}}{-2} =\frac{2\sqrt{3}}{-1} $
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