9a+10(6a-1)=128

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Solution for 9a+10(6a-1)=128 equation: 



9a+10(6a-1)=128

We move all terms to the left:

9a+10(6a-1)-(128)=0

We multiply parentheses

9a+60a-10-128=0

We add all the numbers together, and all the variables

69a-138=0

We move all terms containing a to the left, all other terms to the right

69a=138

a=138/69

a=2

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