64m2=121

Solution for 64m2=121 equation:

64m^2=121

We move all terms to the left:

64m^2-(121)=0

a = 64; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·64·(-121)
Δ = 30976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{30976}=176$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-176}{2*64}=\frac{-176}{128}
=-1+3/8
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+176}{2*64}=\frac{176}{128}
=1+3/8
$