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9=9v+4)/(v+12)
We move all terms to the left:
9-(9v+4)/(v+12))=0
Domain of the equation: (v+12))+9!=0We multiply all the terms by the denominator
v∈R
-(9v+4)=0
We get rid of parentheses
-9v-4=0
We move all terms containing v to the left, all other terms to the right
-9v=4
v=4/-9
v=-4/9
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