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37x-x2=336
We move all terms to the left:
37x-x2-(336)=0
We add all the numbers together, and all the variables
-1x^2+37x-336=0
a = -1; b = 37; c = -336;
Δ = b2-4ac
Δ = 372-4·(-1)·(-336)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-5}{2*-1}=\frac{-42}{-2} =+21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+5}{2*-1}=\frac{-32}{-2} =+16 $
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