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(2x-14)(3x-15)=0
We multiply parentheses ..
(+6x^2-30x-42x+210)=0
We get rid of parentheses
6x^2-30x-42x+210=0
We add all the numbers together, and all the variables
6x^2-72x+210=0
a = 6; b = -72; c = +210;
Δ = b2-4ac
Δ = -722-4·6·210
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-12}{2*6}=\frac{60}{12} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+12}{2*6}=\frac{84}{12} =7 $
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