9=9(m+1)(2m+1)/6

Solution for 9=9(m+1)(2m+1)/6 equation:

9=9(m+1)(2m+1)/6

We move all terms to the left:

9-(9(m+1)(2m+1)/6)=0

We multiply parentheses ..

-(9(+2m^2+m+2m+1)/6)+9=0

We multiply all the terms by the denominator


-(9(+2m^2+m+2m+1)+9*6)=0


We calculate terms in parentheses: -(9(+2m^2+m+2m+1)+9*6), so:

9(+2m^2+m+2m+1)+9*6

We add all the numbers together, and all the variables

9(+2m^2+m+2m+1)+54

We multiply parentheses

18m^2+9m+18m+9+54

We add all the numbers together, and all the variables

18m^2+27m+63

Back to the equation:

-(18m^2+27m+63)


We get rid of parentheses

-18m^2-27m-63=0

a = -18; b = -27; c = -63;
Δ = b2-4ac
Δ = -272-4·(-18)·(-63)
Δ = -3807
Delta is less than zero, so there is no solution for the equation