9=m(m+1)(2m+1)/6

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Solution for 9=m(m+1)(2m+1)/6 equation: 



9=m(m+1)(2m+1)/6

We move all terms to the left:

9-(m(m+1)(2m+1)/6)=0

We multiply parentheses ..

-(m(+2m^2+m+2m+1)/6)+9=0

We multiply all the terms by the denominator


-(m(+2m^2+m+2m+1)+9*6)=0



We calculate terms in parentheses: -(m(+2m^2+m+2m+1)+9*6), so:

m(+2m^2+m+2m+1)+9*6

We add all the numbers together, and all the variables

m(+2m^2+m+2m+1)+54

We multiply parentheses

2m^3+m^2+2m^2+m+54

We do not support empression: m^3

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