9=6(u+2)-3u

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Solution for 9=6(u+2)-3u equation: 



9=6(u+2)-3u

We move all terms to the left:

9-(6(u+2)-3u)=0



We calculate terms in parentheses: -(6(u+2)-3u), so:

6(u+2)-3u

We add all the numbers together, and all the variables

-3u+6(u+2)

We multiply parentheses

-3u+6u+12

We add all the numbers together, and all the variables

3u+12

Back to the equation:

-(3u+12)



We get rid of parentheses

-3u-12+9=0

We add all the numbers together, and all the variables

-3u-3=0

We move all terms containing u to the left, all other terms to the right

-3u=3

u=3/-3

u=-1

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