4(1/4)=1(3/4)+p=

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Solution for 4(1/4)=1(3/4)+p= equation: 



4(1/4)=1(3/4)+p=

We move all terms to the left:

4(1/4)-(1(3/4)+p)=0



Domain of the equation: 4)+p)!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

-(1(+3/4)+p)+4(+1/4)=0

We add all the numbers together, and all the variables

-(1(+3/4)+p)+1=0

We multiply all the terms by the denominator


-(1(+3+1*4)+p)=0



We calculate terms in parentheses: -(1(+3+1*4)+p), so:

1(+3+1*4)+p

determiningTheFunctionDomain
p+1(+3+1*4)

We add all the numbers together, and all the variables

p+17

Back to the equation:

-(p+17)



We get rid of parentheses

-p-17=0

We add all the numbers together, and all the variables

-1p-17=0

We move all terms containing p to the left, all other terms to the right

-p=17

p=17/-1

p=-17

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