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9=3x(5x-2)
We move all terms to the left:
9-(3x(5x-2))=0
We calculate terms in parentheses: -(3x(5x-2)), so:We get rid of parentheses
3x(5x-2)
We multiply parentheses
15x^2-6x
Back to the equation:
-(15x^2-6x)
-15x^2+6x+9=0
a = -15; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·(-15)·9
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-24}{2*-15}=\frac{-30}{-30} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+24}{2*-15}=\frac{18}{-30} =-3/5 $
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