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9=2(c-3)+3
We move all terms to the left:
9-(2(c-3)+3)=0
We calculate terms in parentheses: -(2(c-3)+3), so:We get rid of parentheses
2(c-3)+3
We multiply parentheses
2c-6+3
We add all the numbers together, and all the variables
2c-3
Back to the equation:
-(2c-3)
-2c+3+9=0
We add all the numbers together, and all the variables
-2c+12=0
We move all terms containing c to the left, all other terms to the right
-2c=-12
c=-12/-2
c=+6
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