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4(2+y)=3(1+y)
We move all terms to the left:
4(2+y)-(3(1+y))=0
We add all the numbers together, and all the variables
4(y+2)-(3(y+1))=0
We multiply parentheses
4y-(3(y+1))+8=0
We calculate terms in parentheses: -(3(y+1)), so:We get rid of parentheses
3(y+1)
We multiply parentheses
3y+3
Back to the equation:
-(3y+3)
4y-3y-3+8=0
We add all the numbers together, and all the variables
y+5=0
We move all terms containing y to the left, all other terms to the right
y=-5
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