9=-3(b+-10)+-9

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Solution for 9=-3(b+-10)+-9 equation: 



9=-3(b+-10)+-9

We move all terms to the left:

9-(-3(b+-10)+-9)=0

We add all the numbers together, and all the variables

-(-3(b-10)+-9)+9=0

We use the square of the difference formula

-(-3(b-10)-9)+9=0



We calculate terms in parentheses: -(-3(b-10)-9), so:

-3(b-10)-9

We multiply parentheses

-3b+30-9

We add all the numbers together, and all the variables

-3b+21

Back to the equation:

-(-3b+21)



We get rid of parentheses

3b-21+9=0

We add all the numbers together, and all the variables

3b-12=0

We move all terms containing b to the left, all other terms to the right

3b=12

b=12/3

b=4

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