((3x+2)-(x-1))+(2x-5+3x+7)=-4x+37

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Solution for ((3x+2)-(x-1))+(2x-5+3x+7)=-4x+37 equation:



((3x+2)-(x-1))+(2x-5+3x+7)=-4x+37
We move all terms to the left:
((3x+2)-(x-1))+(2x-5+3x+7)-(-4x+37)=0
We add all the numbers together, and all the variables
((3x+2)-(x-1))+(5x+2)-(-4x+37)=0
We get rid of parentheses
((3x+2)-(x-1))+5x+4x+2-37=0
We calculate terms in parentheses: +((3x+2)-(x-1)), so:
(3x+2)-(x-1)
We get rid of parentheses
3x-x+2+1
We add all the numbers together, and all the variables
2x+3
Back to the equation:
+(2x+3)
We add all the numbers together, and all the variables
9x+(2x+3)-35=0
We get rid of parentheses
9x+2x+3-35=0
We add all the numbers together, and all the variables
11x-32=0
We move all terms containing x to the left, all other terms to the right
11x=32
x=32/11
x=2+10/11

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