98=(17-2x)(9-2x)

Solution for 98=(17-2x)(9-2x) equation:

98=(17-2x)(9-2x)

We move all terms to the left:

98-((17-2x)(9-2x))=0

We add all the numbers together, and all the variables

-((-2x+17)(-2x+9))+98=0

We multiply parentheses ..

-((+4x^2-18x-34x+153))+98=0


We calculate terms in parentheses: -((+4x^2-18x-34x+153)), so:

(+4x^2-18x-34x+153)

We get rid of parentheses

4x^2-18x-34x+153

We add all the numbers together, and all the variables

4x^2-52x+153

Back to the equation:

-(4x^2-52x+153)


We get rid of parentheses

-4x^2+52x-153+98=0

We add all the numbers together, and all the variables

-4x^2+52x-55=0

a = -4; b = 52; c = -55;
Δ = b2-4ac
Δ = 522-4·(-4)·(-55)
Δ = 1824
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1824}=\sqrt{16*114}=\sqrt{16}*\sqrt{114}=4\sqrt{114}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-4\sqrt{114}}{2*-4}=\frac{-52-4\sqrt{114}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+4\sqrt{114}}{2*-4}=\frac{-52+4\sqrt{114}}{-8}
$