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-52(3-x)=102/5(x+5)
We move all terms to the left:
-52(3-x)-(102/5(x+5))=0
Domain of the equation: 5(x+5))!=0We add all the numbers together, and all the variables
x∈R
-52(-1x+3)-(102/5(x+5))=0
We multiply parentheses
52x-(102/5(x+5))-156=0
We multiply all the terms by the denominator
52x*5(x+5))-(102-156*5(x+5))=0
Wy multiply elements
260x^2(x-780x(x=0
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