96t2-294=0

Solution for 96t2-294=0 equation:

96t^2-294=0

a = 96; b = 0; c = -294;
Δ = b2-4ac
Δ = 02-4·96·(-294)
Δ = 112896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{112896}=336$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-336}{2*96}=\frac{-336}{192}
=-1+3/4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+336}{2*96}=\frac{336}{192}
=1+3/4
$