2t-(7t-1)+3(2t-3)=4(7-2t)

Solution for 2t-(7t-1)+3(2t-3)=4(7-2t) equation:

2t-(7t-1)+3(2t-3)=4(7-2t)

We move all terms to the left:

2t-(7t-1)+3(2t-3)-(4(7-2t))=0

We add all the numbers together, and all the variables

2t-(7t-1)+3(2t-3)-(4(-2t+7))=0

We multiply parentheses

2t-(7t-1)+6t-(4(-2t+7))-9=0

We get rid of parentheses

2t-7t+6t-(4(-2t+7))+1-9=0


We calculate terms in parentheses: -(4(-2t+7)), so:

4(-2t+7)

We multiply parentheses

-8t+28

Back to the equation:

-(-8t+28)


We add all the numbers together, and all the variables

t-(-8t+28)-8=0

We get rid of parentheses

t+8t-28-8=0

We add all the numbers together, and all the variables

9t-36=0

We move all terms containing t to the left, all other terms to the right

9t=36

t=36/9

t=4