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96=2x(x+8)
We move all terms to the left:
96-(2x(x+8))=0
We calculate terms in parentheses: -(2x(x+8)), so:We get rid of parentheses
2x(x+8)
We multiply parentheses
2x^2+16x
Back to the equation:
-(2x^2+16x)
-2x^2-16x+96=0
a = -2; b = -16; c = +96;
Δ = b2-4ac
Δ = -162-4·(-2)·96
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-32}{2*-2}=\frac{-16}{-4} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+32}{2*-2}=\frac{48}{-4} =-12 $
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